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Sagot :
let the weight of the first truck be represented by w.
total weight = w + (2 + w) + (2 + 2 + w) + (2 + 2 + 2 + w)
32 = 4w + 12
20 = 4w
w = 5
Therefore, the first truck weighs 5 tons, the second weighs 7 tons, the third weighs 9 tons and the fourth weighs 11 tons.
total weight = w + (2 + w) + (2 + 2 + w) + (2 + 2 + 2 + w)
32 = 4w + 12
20 = 4w
w = 5
Therefore, the first truck weighs 5 tons, the second weighs 7 tons, the third weighs 9 tons and the fourth weighs 11 tons.
Answer:
The weights of the trucks are 5, 7, 9 and 11 tons respectively.
Step-by-step explanation:
Let the weight of first truck = x ( in tons ).
It is given that the weight of the trucks is increasing by 2 tons after the first truck.
So, we get,
Truck Weight
1 x
2 x+2
3 x+2+2 = x+4
4 x+4+2 = x+6
Since, the total weights of the trucks is 32 tons. We get,
[tex]x+(x+2)+(x+4)+(x+6)=32[/tex]
i.e. [tex]4x+12=32[/tex]
i.e. [tex]4x=20[/tex]
i.e. x= 5
So, the weight of the first truck is 5 tons.
Then, we have,
The weight of 2nd truck = 5+2 = 7 tons
The weight of 2nd truck = 5+4 = 9 tons
The weight of 2nd truck = 5+6 = 11 tons
Hence, the weights of the trucks are 5, 7, 9 and 11 tons respectively.
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