Tiffany612
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Help with these 2 questions please?? Check my answers.
The height of a triangle is 13 in. less than its base. If the area of the triangle is 24 in2, what is the length of the base?

3 in.
10 in.<------
16 in.
21 in.




Madison hits a tennis ball with an initial velocity of 18 m/s straight up into the air. When she hits the ball, it is 1.2 m above the ground. Which equation can be used to find the time, t, it takes for the ball to reach the ground?

–4.9t2 + 18t + 1.2 = 0
–16t2 + 18t + 1.2 = 0<-------
–4.9t2 + 1.2t + 18 = 0
–16t2 + 1.2t + 18 = 0

Sagot :

rabinshrestha41
1>
Let the base be "x"
According to the question, 

h = x - 13

A = 24 in sq.
Now,
[tex] Area of triangle = \frac{1}{2}~b~h [/tex]

[tex]24= \frac{1}{2}(x)(x-13) [/tex]

[tex]24 *2= (x)(x-13) [/tex]

[tex]48= x^{2} - 13x[/tex]

[tex]0= x^{2} - 13x -48[/tex]

Factorizing the equation,  x²  - 13x  -48, we get,

[tex]0= x^{2}+3x - 16x -48[/tex]

[tex]0= x(x+3) - 16(x+3)[/tex]

[tex]0= (x + 3)(x-16)[/tex]

NOW, using zero product property, we get,

Either,
x + 3 = 0 
     x = -3

Or,
x - 16 = 0
      x  = 16

Since, distance can't be negative, we have, x = 16 in.
So, the length of the base is 16 inches.

2>

umm...i don't know how to do it...can you post a picture of the same kind of (solved) question....i mean like an example


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