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Sagot :
1 in 12 chance of second person getting given a ticket
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance
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