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Sagot :
Take the first bracket and it's multiplication, 3(2a+5)
You expand my multiplying everything inside the bracket by the number outside.
3*2a = 6a
3*5 = 15
Then multiply out the second bracket, 5(a-2)
5*a = 5a
5*-2 = -10
So now you have 6a + 15 + 5a - 10
Simplify it by collecting like terms, and you have:
11a + 5
And that's the answer, hope I helped!
You expand my multiplying everything inside the bracket by the number outside.
3*2a = 6a
3*5 = 15
Then multiply out the second bracket, 5(a-2)
5*a = 5a
5*-2 = -10
So now you have 6a + 15 + 5a - 10
Simplify it by collecting like terms, and you have:
11a + 5
And that's the answer, hope I helped!
First of all you need to expand this expression. you do this by multiplying the number outside the brackets with each term inside the brackets. this is the first one ; 3 x 2a = 6a, 3 x 5 = 15. the extra + sign in the first brackets stays between the two terms, so the first set of brackets is now 6a + 15. now we have to look at the second ; 5 x a = 5a, 5 x 2 = 10, like the extra + sign, the extra - sign stays between the two terms as well, so the second bracket is now 5a-10. you put them together to get 6a + 15 + 5a - 10.
next you need to simplify the expression. first you need to group like terms, e.g. the numbers and the letters. 6a + 15 +5a -10. the 6a + 5a = 11a and the 15 - 10 = +5. you then put these two terms together to get your final answer of
11a + 5
next you need to simplify the expression. first you need to group like terms, e.g. the numbers and the letters. 6a + 15 +5a -10. the 6a + 5a = 11a and the 15 - 10 = +5. you then put these two terms together to get your final answer of
11a + 5
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