Lavona85
Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Marley drives to work every day and passes two independently operated traffic lights. The probability that both lights are red is 0.35. The probability that the first light is red is 0.48. What is the probability that the second light is red, given that the first light is red?
a)0.13
b)0.35
c)0.48
d)0.73

Sagot :

chipperrider
Let event A be the first light being red.
Let event B be the second light being red.

P(A) = 0.48
P(A & B) = P(A) * P(B) = 0.35

P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73

Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.
IwAsSoMeGuY
Overall probability = Probability1 *Probability2
Using the data you already have, you can fill it in as
0.35 = 0.48 * P2
Rearrange to isolate P2, by dividing both sides by 0.48, so
0.35/0.48 = P2
P2 = 0.7291666..., which rounded to two d.p is 0.73
So d)0.73 is correct
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.