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Sagot :
Let event A be the first light being red.
Let event B be the second light being red.
P(A) = 0.48
P(A & B) = P(A) * P(B) = 0.35
P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73
Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.
Let event B be the second light being red.
P(A) = 0.48
P(A & B) = P(A) * P(B) = 0.35
P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73
Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.
Overall probability = Probability1 *Probability2
Using the data you already have, you can fill it in as
0.35 = 0.48 * P2
Rearrange to isolate P2, by dividing both sides by 0.48, so
0.35/0.48 = P2
P2 = 0.7291666..., which rounded to two d.p is 0.73
So d)0.73 is correct
Using the data you already have, you can fill it in as
0.35 = 0.48 * P2
Rearrange to isolate P2, by dividing both sides by 0.48, so
0.35/0.48 = P2
P2 = 0.7291666..., which rounded to two d.p is 0.73
So d)0.73 is correct
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