Answered

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Simplify (1-cosΘ)(1+cosΘ) / (1-sinΘ)/(1+sinΘ)?

Sagot :

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[tex] \frac{(1-cosx)(1+cosx)}{(1-sinx)(1+sinx)} \\ \\ \frac{1-cos^2x}{1-sin^2x} \\ \\ \frac{sin^2x}{cos^2x} \\ \\ tan^2x[/tex]
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