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Sagot :
first, you add up the non-$10 winning cars so 100+25=125.
then you take 5:125 because you want the winning 10$ against not winning. the to get 1 you divide both numbert by 5 to get 1 on the left. so you get 1:25.
hope i helped:)
then you take 5:125 because you want the winning 10$ against not winning. the to get 1 you divide both numbert by 5 to get 1 on the left. so you get 1:25.
hope i helped:)
The odds against winning less than $10 is 1/25 and this can be determined by using the given data.
Given :
- A green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10.
- 100 green tickets, 25 yellow tickets, and 5 blue tickets.
The following steps can be used in order to determine the odds against winning less than $10:
Step 1 - The total number of green tickets and yellow tickets is 125 (100+25).
Step 2 - Let the odds against winning less than $10 be 'x'.
Step 3 - So, the value of 'x' is calculated as:
[tex]x = \dfrac{5}{125}[/tex]
[tex]x = \dfrac{1}{25}[/tex]
Therefore, the correct option is D).
For more information, refer to the link given below:
https://brainly.com/question/795909
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