Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
You asked a question similar to this recently. This time I will show the multiplication and subtraction method instead of the substitution one.
2x-5y=-5 | x+2y=11
2x-5y=-5 | 2x+4y=22
Subtract the first equation form the second.
9y=27
y=3
Then substitute.
x+2(3)=11
x+6=11
x=5
The final answer is the ordered pair (5,3).
Im using the substitution method because i feel that its easier but you can use any method you prefer. You would start with one equation and isolate a variable( leave it by itself). I started with the second equation (x+2y=11) because the variable x does not have a coeficcient (the number before the variable). I just subtracted 2y from both sides of the equation and got x=-2y+11 or x=11-2y (same thing). Then i substituted or plugged in -2y+11 as x in the firth equation so it would be 2(-2y+11)-5y=-5 . Then i would distribute to get -4y+22-5y=-5 and combine like terms to solve and get that y=3. Then just plug in 3 as y in the second equation and solve for x to get that x=5 and y=3 making your ordered pairs (5,3). Ps sorry if it was long hope i helped
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.