At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
You asked a question similar to this recently. This time I will show the multiplication and subtraction method instead of the substitution one.
2x-5y=-5 | x+2y=11
2x-5y=-5 | 2x+4y=22
Subtract the first equation form the second.
9y=27
y=3
Then substitute.
x+2(3)=11
x+6=11
x=5
The final answer is the ordered pair (5,3).
Im using the substitution method because i feel that its easier but you can use any method you prefer. You would start with one equation and isolate a variable( leave it by itself). I started with the second equation (x+2y=11) because the variable x does not have a coeficcient (the number before the variable). I just subtracted 2y from both sides of the equation and got x=-2y+11 or x=11-2y (same thing). Then i substituted or plugged in -2y+11 as x in the firth equation so it would be 2(-2y+11)-5y=-5 . Then i would distribute to get -4y+22-5y=-5 and combine like terms to solve and get that y=3. Then just plug in 3 as y in the second equation and solve for x to get that x=5 and y=3 making your ordered pairs (5,3). Ps sorry if it was long hope i helped
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.