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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is the approximate percent error?

Sagot :

lulu1991
According to the accepted density of CO2, we can get that 0.10 g CO2 has a volume of 0.10/1.96=0.051 L (theoretical value). The percent error = (0.056 - 0.051)/0.051 * 100% = 9.80%.
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