Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

h(x)=2x²+x-10
2x²+x-10=0

Sagot :

AyaZ
[tex]2 x^{2} +x-10=0 \\ \\ (2x+5)(x-2)=0 \\ \\ x_{1} =- \frac{5}{2} \\ x_{2} =2[/tex]
h(x)=2x2+x-10

2x²+x-10=0

(2x+5)(x-2)

x=-5/2
x=2


1)

h(x)=2x²+x-10
h(-5/2)= 2(-25/4)+[-5/2]-10
h(-5/2)=-25




2).

h(x)=2x²+x-10
h(2)=2(2)²+2-10
h(2)=8+(-8)
h(2)=0
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.