Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A flashlight has a filament with a resistance of 9.8 Ohms. If the batteries provide 3.0 V, what is the current through the filament?

Sagot :

AL2006

Current = (voltage) / (resistance)

Current= (3.0volts) / (9.8 ohms)  =  0.306 ampere = 306 milliamperes (mA)

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.