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A flashlight has a filament with a resistance of 9.8 Ohms. If the batteries provide 3.0 V, what is the current through the filament?

Sagot :

AL2006

Current = (voltage) / (resistance)

Current= (3.0volts) / (9.8 ohms)  =  0.306 ampere = 306 milliamperes (mA)

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