Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
[tex]A=lw \Rightarrow l=\frac{A}{w}[/tex]
A - area, l - length, w - width
[tex]w=x-2 \\ A=x^3-2x-4 \\ \\ l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}= \\ =\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2[/tex]
The answer is D. x²+2x+2.
A - area, l - length, w - width
[tex]w=x-2 \\ A=x^3-2x-4 \\ \\ l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}= \\ =\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2[/tex]
The answer is D. x²+2x+2.
Answer:
D. [tex]x^2+2x+2[/tex]
Step-by-step explanation:
We know that,
The area of a rectangle is,
A = l × b,
Where, l is the length of the rectangle,
w is the width of the rectangle,
Given,
[tex]A = x^3-2x-4[/tex]
[tex]w=(x-2)[/tex]
By substituting values,
[tex]x^3-2x-4=(x-2)l[/tex]
[tex]\implies l = \frac{x^3-2x-4}{x-2}=x^2+2x+2[/tex] ( By long division shown below )
Hence, the length of the rectangular garden is [tex]x^2+2x+2[/tex]
Option D is correct.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.