Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
1. 200/2=100. 100/2=50. 50/2=25. So that's 3 to get to 25.
2. 11.46/3=3.82
The answer is (2).
2. 11.46/3=3.82
The answer is (2).
Answer : The correct option is, (2) 3.82 d
Solution : Given,
As we know that the radioactive decays follow first order kinetics.
So, the expression for rate law for first order kinetics is given by :
[tex]k=\frac{2.303}{t}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = time taken for decay process = 11.46 days
a = initial amount of the reactant = 200 g
a - x = amount left after decay process = 25 g
Putting values in above equation, we get the value of rate constant.
[tex]k=\frac{2.303}{11.46}\log\frac{200}{25}=0.1814[/tex]
Now we have to calculate the half life of a radioisotope.
Formula used : [tex]t_{1/2}=\frac{0.693}{k}[/tex]
Putting value of 'k' in this formula, we get the half life.
[tex]t_{1/2}=\frac{0.693}{0.1814}=3.820[/tex]
Therefore, the half-life of a radioisotope is, 3.820 d
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.