Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
[tex]The\ volume\ of\ the\ cone:V=\frac{1}{3}\pi r^2H\\\\where\\r-radius\\H-height\\----------------\\\\r=8\ in\ and\ H=12\ in\\\\therefore\\\\V=\frac{1}3{\pi\cdot8^2\cdot12=\frac{1}{\not3_1}\cdot\frac{\not12^4}{1}\cdot64\pi=4\cdot64\pi=\boxed{256\pi\ (in^3)}[/tex]
Volume = [tex]256\pi in ^{3}[/tex]
Work is attached in the image provided.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.