Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What is the total amount of heat absorbed by 100.0 grams of water when the temperature of the water is increased from 30.0°C to 45.0°C?
(1) 418 J (3) 12 500 J
(2) 6270 J (4) 18 800 J

Sagot :

eradaniel
The total amount of heat is the same as the energy. Because no phase change is occurring, use the formula Q = mc(delta)T. Q is the energy, m is the mass, c is the specific heat capacity of water as a liquid, and (delta)T is the change in temperature. So: Q = (100.0 g)(4.186 J/g°C)(15°C); Q = 6279 Joules.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.