Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The volume of sample when the gas is heated to 303 K is [tex]\boxed{{\text{(2)6}}{\text{.2 L}}}[/tex]
Further explanation:
Charles’s law:
Charles’s work showed that at constant pressure, the volume-temperature relationship for a fixed amount of gas is linear. In other words, Charles’s law can be stated that at constant pressure, the volume occupied by a fixed amount of a gas is directly proportional to its absolute temperature (Kelvin). This relationship is known as Charles’s law.
The mathematical representation of Charles’s law is,
[tex]{\mathbf{V}}\propto{\mathbf{T}}[/tex] [P and n are constant]
Where,
⦁ V is volume occupied by the fixed quantity of gas.
⦁ T is the temperature of a gas.
⦁ P is the pressure of a gas.
⦁ n denotes the number of moles of gas.
The relationship can also be expressed as,
[tex]\frac{{\text{V}}}{{\text{T}}} = {\text{constant}}[/tex] [P and n are constant]
Or it can also be expressed as follows:
[tex]\frac{{{{\text{V}}_{\text{1}}}}}{{{{\text{T}}_{\text{1}}}}} = \frac{{{{\text{V}}_{\text{2}}}}}{{{{\text{T}}_{\text{2}}}}}[/tex] …… (1)
Here,
[tex]{{\text{V}}_1}[/tex] is the initial volume of gas.
[tex]{{\text{V}}_2}[/tex] is the final volume of gas.
[tex]{{\text{T}}_1}[/tex] is the initial temperature of the gas.
[tex]{{\text{T}}_2}[/tex] is the final temperature of the gas.
Rearrange equation (1) to calculate [tex]{{\text{V}}_2}[/tex] .
[tex]{{\text{V}}_{\text{2}}} = \frac{{{{\text{V}}_{\text{1}}}{{\text{T}}_{\text{2}}}}}{{{{\text{T}}_{\text{1}}}}}[/tex] …… (2)
The value of [tex]{{\text{V}}_1}[/tex] is 6 L.
The value of [tex]{{\text{T}}_1}[/tex] is 293 K.
The value of [tex]{{\text{T}}_2}[/tex] is 303 K.
Substitute these values in equation (2).
[tex]\begin{aligned}{{\text{V}}_{\text{2}}}&=\frac{{\left({{\text{6 L}}}\right)\left( {{\text{303 K}}}\right)}}{{\left( {{\text{293 K}}}\right)}}\\&={\text{6}}{\text{.20477 L}}\\&\approx{\mathbf{6}}{\mathbf{.2 L}}\\\end{aligned}[/tex]
So option (2) is the correct answer.
Learn more:
1. Law of conservation of matter states: https://brainly.com/question/2190120
2. Calculation of volume of gas: https://brainly.com/question/3636135
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Ideal gas equation
Keywords: Charles’s law, volume, temperature, pressure, volume temperature relationship, absolute temperature, constant pressure, relationship, V directly proportional to T, ideal gas, ideal gas equation number of moles, moles, P, n, V, T, volume of gas, 6.2 L, 303 K, 293 K, 6 L.
The volume of the sample after the gas is heated to 303 K is 6.2 L
The correct answer to the question is Option (2) 6.2 L
From the question given above, the following data were obtained:
Initial volume (V₁) = 6 L
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 303 K
Pressure = constant
Final volume (V₂) =?
Using the Charles' law equation, we can obtain the final volume of the gas as follow:
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\\\frac{6}{293} = \frac{V_{2}}{303}\\\\[/tex]
Cross multiply
293 × V₂ = 6 × 303
293 × V₂ = 1818
Divide both side by 293
[tex]V_{2} = \frac{1818}{293}\\\\[/tex]
V₂ = 6.2 L
Therefore, the volume of the sample after the gas is heated to 303 K is 6.2 L
The correct answer to the question is Option (2) 6.2 L
Learn more: https://brainly.com/question/16927784
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
