Answered

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Which element requires the least amount of energy to remove the most loosely held electron from a gaseous atom in the ground state?
(1) bromine (3) sodium
(2) calcium (4) silver

Sagot :

lulu1991
The answer is (3) sodium. The sodium has only one electron at the outer layer. While calcium has 2 and bromine has 7. And silver is usually not easy to react. So the sodium is the easiest one to lose one electron,

The element sodium (Na) in the periodic table requires the least amount of energy to remove the most loosely held electron. Thus, option 3 is correct.

What is the trend of sodium?

The periodic table is the arrangement of the elements based on their physical and chemical properties. The sodium element requires the minimum energy to eliminate the electron from its outer shell.

The sodium element has low nuclear energy and small size making the shielding effect to be negligible. The loss of an electron from the outer shell results in the achievement of a stable configuration.

Thus, sodium requires the least energy.

Learn more about elements here:

https://brainly.com/question/11576731

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