Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Which element requires the least amount of energy to remove the most loosely held electron from a gaseous atom in the ground state?
(1) bromine (3) sodium
(2) calcium (4) silver

Sagot :

lulu1991
The answer is (3) sodium. The sodium has only one electron at the outer layer. While calcium has 2 and bromine has 7. And silver is usually not easy to react. So the sodium is the easiest one to lose one electron,

The element sodium (Na) in the periodic table requires the least amount of energy to remove the most loosely held electron. Thus, option 3 is correct.

What is the trend of sodium?

The periodic table is the arrangement of the elements based on their physical and chemical properties. The sodium element requires the minimum energy to eliminate the electron from its outer shell.

The sodium element has low nuclear energy and small size making the shielding effect to be negligible. The loss of an electron from the outer shell results in the achievement of a stable configuration.

Thus, sodium requires the least energy.

Learn more about elements here:

https://brainly.com/question/11576731

#SPJ5

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.