Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
What you have to do it find the percentage / solve it. Divide the mass by the entire mass.
239.7 ÷ 266.68 = 0.898 × 100 = 90% Br.
239.7 ÷ 266.68 = 0.898 × 100 = 90% Br.
Answer: The correct answer is option(4).
Explanation:
Molar mass of the aluminium bromide, [tex]AlBr_3=266.69 g/mol[/tex]
Atomic mass of bromine = 79.90 g/mol
Percentage of Mass of bromine in [tex]AlBr_3[/tex]:
[tex]\% Br\text{ by mass}=\frac{\text{Atomic mass of Br}\times \text{Number of Br atoms}\times 100}{\text{Molar mass of }AlBr_3}[/tex]
[tex]\% Br\text{ by mass}=\frac{79.90 g/mol\times 3\times 100}{266.69 g/mol}=89.97\%\approx 90\%[/tex]
Hence, the correct answer is option(4).
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.