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At what point does the graph of 5x + 4y = 12 intersect the y-axis?
a. (0, 3)
b. (0, -3)
c. (3, 0)
d. (5, 0)
e. (0, -5)

Sagot :

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To find the y-intercept, we need to re-arrange the equation given to y=mx+c, where c is the y-intercept
To do this to 5x + 4y = 12, we need to have only y on the left side, so subtract 5x from each side, to get
4y = 12 - 5x, or
4y = -5x + 12
Now we need to isolate y, so divide each side by 4
y = 5/4x + 3
So the y-intercept will be at +3, and the y intercept is always on x = 0, so the co-ordinate will be (0, 3), which is a.
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