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if the perimeter of the rectangle is 48, find the dimensions

Sagot :

apologiabiology
p=perimeter
l=legnth
w=width
so perimiter of rectangle=legnth+legnth+width+widht or
p=2l+2w or  undistribute the 2
p=2(l+w)
if p=48 then
48=2(l+w)
divide by 2
24=l+w
so the answer is l+w=24
l=24-w
w=l-24
subsitue
legnth>width
answeres could be:
L,W
23,1
22,2
21,3
20,4
19,5
18,6
17,7
16,8
15,9
14,10
13,11
and that is only the integer pairs
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