Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Volume of a sphere is (4/3)(pi)(r^3)
(4/3)(pi)(6^3) = 904.78
(4/3)(pi)(24^3) = 57905.84
57905.84 - 904.78 = 57001.06cm^3 more plaster
(4/3)(pi)(6^3) = 904.78
(4/3)(pi)(24^3) = 57905.84
57905.84 - 904.78 = 57001.06cm^3 more plaster
volume of a sphere is 4/3 times pi times radius^3
so first calculate the smaler sphere
radius=6
pi is aprox 3.14
4/3 times 3.14 times r^3
4/3 times 3.14 times 6^3
4/3 times 3.14 times 216
904.32 cm^3=volume
volume of larger
radius=24
4/3 times 3.14 times 24^3
4/3 times 3.14 times 13824
57876.48 cm^3
so then subtract the volume of the smaller sphere from the larger sphere
57876.48-904.32=56972.16 cm
he used
56972.16 cm^3 plaster
I think you mean to the hundreth's place which is the place denoted by the x in 0.0x so it is to the hundreth's place
he used
56972.16 cm^3 plaster
I got this from The Brainliest Answer!
so first calculate the smaler sphere
radius=6
pi is aprox 3.14
4/3 times 3.14 times r^3
4/3 times 3.14 times 6^3
4/3 times 3.14 times 216
904.32 cm^3=volume
volume of larger
radius=24
4/3 times 3.14 times 24^3
4/3 times 3.14 times 13824
57876.48 cm^3
so then subtract the volume of the smaller sphere from the larger sphere
57876.48-904.32=56972.16 cm
he used
56972.16 cm^3 plaster
I think you mean to the hundreth's place which is the place denoted by the x in 0.0x so it is to the hundreth's place
he used
56972.16 cm^3 plaster
I got this from The Brainliest Answer!
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.