At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Volume of a sphere is (4/3)(pi)(r^3)
(4/3)(pi)(6^3) = 904.78
(4/3)(pi)(24^3) = 57905.84
57905.84 - 904.78 = 57001.06cm^3 more plaster
(4/3)(pi)(6^3) = 904.78
(4/3)(pi)(24^3) = 57905.84
57905.84 - 904.78 = 57001.06cm^3 more plaster
volume of a sphere is 4/3 times pi times radius^3
so first calculate the smaler sphere
radius=6
pi is aprox 3.14
4/3 times 3.14 times r^3
4/3 times 3.14 times 6^3
4/3 times 3.14 times 216
904.32 cm^3=volume
volume of larger
radius=24
4/3 times 3.14 times 24^3
4/3 times 3.14 times 13824
57876.48 cm^3
so then subtract the volume of the smaller sphere from the larger sphere
57876.48-904.32=56972.16 cm
he used
56972.16 cm^3 plaster
I think you mean to the hundreth's place which is the place denoted by the x in 0.0x so it is to the hundreth's place
he used
56972.16 cm^3 plaster
I got this from The Brainliest Answer!
so first calculate the smaler sphere
radius=6
pi is aprox 3.14
4/3 times 3.14 times r^3
4/3 times 3.14 times 6^3
4/3 times 3.14 times 216
904.32 cm^3=volume
volume of larger
radius=24
4/3 times 3.14 times 24^3
4/3 times 3.14 times 13824
57876.48 cm^3
so then subtract the volume of the smaller sphere from the larger sphere
57876.48-904.32=56972.16 cm
he used
56972.16 cm^3 plaster
I think you mean to the hundreth's place which is the place denoted by the x in 0.0x so it is to the hundreth's place
he used
56972.16 cm^3 plaster
I got this from The Brainliest Answer!
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.