Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

calculate the time required for a 6000.-Newton net force to stop a 1200.-kilogram car initially traveling at 10. M/s

Sagot :

AL2006

               Force = (mass) x (acceleration).

We know the force and the mass, so we can write

               6,000 N = (1,200 kg) x (acceleration).

Divide each side by 1,200 kg:       

               Acceleration = 6000N/1200kg = 5 m/s² .

That's the acceleration.  The car's speed changes by 5 m/s each second
that the force acts on it.  If the force pushes from behind, then the car goes
5 m/s faster every second.  If the force pushes from in front, then the car
goes 5 m/s slower every second.

The car is moving at 10 m/s and we want to slow it down to zero m/s.  So
the force has to push from the front, and it will take  (10/5) = 2 seconds to
complete the job.


Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.