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what is x= if (8x^3-9)^3=5832

Sagot :

RedRicin
[tex](8x^3-9)^3=5832[/tex]

Cube root each side.
∛5832 = 18. You can prime factorize to find this.

[tex]8x^3-9=18[/tex]

Add 9 to each side.

[tex]8x^3=27[/tex]

Divide by 8.

[tex]x^3=\frac{27}8[/tex]

Cube root each side.

[tex]\boxed{x=\frac{3}2}[/tex]

Note that radicals with an odd index (cube roots, 5th, 7th, etc.) don't leave a plus-minus...If there's an even number all of the negatives cancel, but if it's odd, it won't, just as with exponents.

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