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Sagot :
The answer is (3) -3. We can know that typically Br has the oxidation state of -1. And the H always has the oxidation state of +1. The total formula needs to have zero oxidation state. So the nitrogen is -3.
Answer : The oxidation number of nitrogen (N) is, (-3)
Explanation :
Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
Rules for Oxidation Numbers :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is, [tex]NH_4Br[/tex]
Let the oxidation state of 'N' be, 'x'
[tex]x+4(+1)+(-1)=0\\\\x+4-1=0\\\\x+3=0\\\\x=-3[/tex]
Therefore, the oxidation number of nitrogen (N) is, (-3)
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