Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer;
(4) 2 L of H2(g) and 2 L of Cl2(g)
Explanation;
- At STP (standard temperature and pressure) 2 L of hydrogen gas and 2 L of chlorine gas will contain the same number of molecules.
- 1 mole of a gas occupies a volume of 22.4 liters at STP. Both hydrogen and chlorine are gases, thus equal volumes of the two gases ( 2 liters) will be equivalent to 2/22.4 moles (0.0893 moles)
- 1 mole is equivalent to 6.0 ×10^23 particles . Thus 2 L of each gas would contain 5.357 × 10 ^22 molecules (0.0893 × 6 ×10^23).
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.