Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Answer;
(4) 2 L of H2(g) and 2 L of Cl2(g)
Explanation;
- At STP (standard temperature and pressure) 2 L of hydrogen gas and 2 L of chlorine gas will contain the same number of molecules.
- 1 mole of a gas occupies a volume of 22.4 liters at STP. Both hydrogen and chlorine are gases, thus equal volumes of the two gases ( 2 liters) will be equivalent to 2/22.4 moles (0.0893 moles)
- 1 mole is equivalent to 6.0 ×10^23 particles . Thus 2 L of each gas would contain 5.357 × 10 ^22 molecules (0.0893 × 6 ×10^23).
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.