Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure is changed to 38.7 kPa?
(1) 31.5 K (3) 566 K(2) 292 K (4) 2360 K

Sagot :

The answer is (3) 566 K. For this problem, you need the combined gas law, which is P1V1/T1 = P2V2/T2 (variables represent Pressure, Volume, and Temperature). You are looking for T2, so you get T2 = P2V2T1/P1V1 = (38.7)(1880)(273)/(79.0)(444) = 566 K.
phillipskaylisa7704

Answer:

566K

Explanation:

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.