Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
You can solve this by setting up 2 equations
if alice is traveling 3 times faster than brenda, we can make an equation
3x=y x is brenda, y is alice
then we can set up an equation based on d=rt
720= (x + y) x 7.5
we can plug in the 1st equation to have the same 2 variables, so for x we can plug in 1/3y or for y we can plug in 3x
720 = (x + 3x) x 7.5
720= 4x x 7.5 divide by 7.5
96 = 4x divide by 4
x= 24
brenda is traveling at 24 miles per hour. We can find alice's speed by plugging x back into the 1st equation
3x = y
3(24)= 72
Alice is going 72 miles per hour
Thanks for making the question, I had to remember how to do this
if alice is traveling 3 times faster than brenda, we can make an equation
3x=y x is brenda, y is alice
then we can set up an equation based on d=rt
720= (x + y) x 7.5
we can plug in the 1st equation to have the same 2 variables, so for x we can plug in 1/3y or for y we can plug in 3x
720 = (x + 3x) x 7.5
720= 4x x 7.5 divide by 7.5
96 = 4x divide by 4
x= 24
brenda is traveling at 24 miles per hour. We can find alice's speed by plugging x back into the 1st equation
3x = y
3(24)= 72
Alice is going 72 miles per hour
Thanks for making the question, I had to remember how to do this
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
