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Sagot :
x/2 x .09 =y
x/2 x .11= z
y + z = 420
((x/2) x .09) + ((x/2) x .11) = 420
.09x/2 + .11x/2 = 420
.2x/2= 420
.1x=420
x=4200
Plug that value back into the originals to check
4200/2 x .09 = 189
4200/2 x .11 = 231
-------
420
She invested 4200 dollars
x/2 x .11= z
y + z = 420
((x/2) x .09) + ((x/2) x .11) = 420
.09x/2 + .11x/2 = 420
.2x/2= 420
.1x=420
x=4200
Plug that value back into the originals to check
4200/2 x .09 = 189
4200/2 x .11 = 231
-------
420
She invested 4200 dollars
If her total annual interest is $420. Then the amount of invested will be $4200.
What is the percentage?
The quantity of anything is stated as though it were a fraction of a hundred.
Emma has half of her investments in stock paying a 9% dividend and the other half in a stock paying 11% interest.
If her total annual interest is $420.
Then the amount of invested will be
Let x be the invested amount.
0.09(x/2) + 0.11(x/2) = 420
(x/2) (0.09 + 0.11) = 420
x/2 = 2100
x = $4200
More about the percentage link is given below.
https://brainly.com/question/8011401
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