Dorothy489
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A saturated solution of NaNO3 is prepared at 60.°C using 100. grams of water. As this solution is cooled to 10.°C, NaNO3 precipitates (settles)
out of the solution. The resulting solution is saturated. Approximately how many grams of NaNO3 settled out of the original solution?
(1) 46 g (3) 85 g
(2) 61 g (4) 126 g

Sagot :

lulu1991
The answer is (1) 46g. This is related to the solubility curve of the NaNO3. The solubility of NaNO3 under 60 ℃ is 126 g. And the solubility under 10 ℃ is 80 g. So the NaNO3 precipitates is 126-80=46 g.
superman1987

The answer is 46 g


The explanation :


According to the attached curve of the relation between the temperature and the grams in solutions:


-we can see from the curve that the grams of NaNO3 at 60°C = 126 g


-and the grams of NaNO3 at 10°C = 80 g


-so, To get the grams of NaNO3 settled out of the original solution, we will subtract the grams of NaNO3 at 10°C - the grams of NaNO3 at 60°C


126 g - 80 g = 46 g


∴ the correct answer is 46 g

View image superman1987
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.