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Sagot :
The answer is (1) 46g. This is related to the solubility curve of the NaNO3. The solubility of NaNO3 under 60 ℃ is 126 g. And the solubility under 10 ℃ is 80 g. So the NaNO3 precipitates is 126-80=46 g.
The answer is 46 g
The explanation :
According to the attached curve of the relation between the temperature and the grams in solutions:
-we can see from the curve that the grams of NaNO3 at 60°C = 126 g
-and the grams of NaNO3 at 10°C = 80 g
-so, To get the grams of NaNO3 settled out of the original solution, we will subtract the grams of NaNO3 at 10°C - the grams of NaNO3 at 60°C
126 g - 80 g = 46 g
∴ the correct answer is 46 g

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