Garnand16
Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

At a certain temperature, 0.660 mol of SO3 is placed in a 3.00-L container.

2SO3(g) <---> 2SO2 + O2(g)

At equilibrium, 0.160 mol of O2 is present. Calculate Kc.

Sagot :

poppopularbee3
When this equilibrium shifts to the right, forming "X" mol of O2
2SO3(g) ---> 2SO2(g) + O2(g) 0.660 - 2X --> --> 2X & X since X = 0.130 this becomes 0.400 <=> 0.260 & 0.130 find moles / litre: (0.400) / 4.5L --> --> 0.260 / 4.5L & 0.130 / 4.5 L which gives these molarities: 2SO3(g) ---> 2SO2(g) + 1 O2(g) [0.08889] --> [0.05778] & [0.02889] Kc = [SO2]^2 [O2] / [SO3]^2 Kc = [0.05778]^2 [0.02889] / [0.08889]^2 Kc = (0.003338) [0.02889] / [(0.007901) Kc = 0.0122
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.