Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
Answer : The excess reagent is, [tex]NaCl[/tex]
Explanation :
First we have to calculate the moles of [tex]NaCl[/tex] and [tex]AgNO_3[/tex].
[tex]\text{Moles of }NaCl=\frac{\text{Mass of }NaCl}{\text{Molar mass of }NaCl}=\frac{4g}{58.4g/mole}=0.068moles[/tex]
[tex]\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{10g}{169.9g/mole}=0.058moles[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
[tex]NaCl+AgNO_3\rightarrow AgCl+NaNO_3[/tex]
From the balanced reaction we conclude that
As, 1 mole of [tex]NaCl[/tex] react with 1 mole of [tex]AgNO_3[/tex]
So, 0.068 moles of [tex]NaCl[/tex] react with 0.068 moles of [tex]AgNO_3[/tex]
From this we conclude that, the moles of [tex]AgNO_3[/tex] are less than the NaCl. So, [tex]AgNO_3[/tex] is a limiting reagent because it limits the formation of products and [tex]NaCl[/tex] is an excess reagent.
Hence, the excess reagent is, [tex]NaCl[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.