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if f(1)=3 and f(n)=-2f(n-1), then f(5)=

Sagot :

AyaZ
[tex]f(n)=-2 f_{n-1} \\ f_{1} =3 \\ f(2)=-2 f_{1}=-2*(3)=-6 \\ f(3)=-2 f_{2}=-2*(-6)=12 \\ f(4)=-2 f_{3}=-2*(12)=-24 \\ f(5)=-2 f_{4}=-2*(-24)=48[/tex]

and

[tex] f_{n} =3* (-2)^{n-1} [/tex]
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