What volume of 0.126 M HCl is needed to neutralize 2.96g of Mg(OH)2?

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08-06-2015
Chemistry

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What volume of 0.126 M HCl is needed to neutralize 2.96g of Mg(OH)2?

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lulu1991 lulu1991 · Answer 1 · 2015-06-08T23:55:40-04:00

lulu1991 lulu1991

08-06-2015

The reaction equation is Mg(OH)2 + 2HCl = MgCl2 + H2O. The mol number of Mg(OH)2 is 2.96/58=0.051 mol. So we need 0.051*2=0.102 mol HCl to neutralize. The volume is 0.102/0.126=0.810 L =810 mL.

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