Answered

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find the domain of f(x)=2x/x^2+9

Sagot :

sbcardinals
The domain is (infinity, infinity)
iloveonedirection
[tex]f(x)= \frac{2x}{x^2+9} \\ \\ x^2+9=0 \\ x^2=-9 \\ x=i \sqrt{3},-i \sqrt{3} \\ \\ domain:(-\infty,\infty)[/tex]
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