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How many grams of TiCl4 are needed to produce 14.7 g of titanium?



Sagot :

This is a stoichiometry problem. The reaction is Ti + 2Cl2 --> TiCl4. You start with a mass of titanium, and you need to end up with mass of titanium (IV) chloride. The basic plan for any stoichiometry problem is Mass of A --> Moles of A --> Moles of B --> Mass of B. So we have Mass of Ti --> Moles of Ti --> Moles of TiCl4 --> Mass of TiCl4, and you get 14.7 g Ti * 1 mol Ti/47.88 g Ti * 1 mol TiCl4/1 mol Ti * 189.68 g TiCl4 / 1 mol TiCl4 = 58.2 g TiCl4. So your answer is 58.2 g
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