AudreaWolffe808
Answered

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A ball is thrown with an initial speed of 10. meters
per second. At what angle above the horizontal
should the ball be thrown to reach the greatest
height?
(1) 0° (3) 45°
(2) 30.° (4) 90.°

Sagot :

sbcardinals
It should be thrown at a 90 degree angle (4) which is the same as throwing it straight up
skyluke89

Answer:

(4) 90.°

Explanation:

The maximum height reached by the ball depends on the vertical velocity of the ball: the greater the vertical velocity of the ball, the higher the ball will go.

The vertical component of the velocity of the ball is given by:

[tex]v_y = v_0 sin \theta[/tex]

where

[tex]v_0 = 10 m/s[/tex] is the initial speed of the ball

[tex]\theta[/tex] is the angle at which the ball is thrown

Therefore, [tex]v_y[/tex] will be maximum when [tex]sin \theta =1[/tex]. And by solving this equation, we find that the angle that satisfies this condition is [tex]\theta=90^{\circ}[/tex], which corresponds to throwing the ball straight up.

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