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Sagot :
4)2.94 • 10^-3 s
Period=(1/frequency)
Period=(1/340Hz)
Period=.0029411765 s
Answer : The correct option is, (4) [tex]2.4\times 10^{-3}s[/tex]
Solution :
The relation between the frequency and time period is that the frequency is inversely proportional to the time period.
It is written as,
[tex]\nu=\frac{1}{T}\\\\T=\frac{1}{\nu}[/tex]
where,
[tex]\nu[/tex] = frequency of the sound wave = 340 Hz = [tex]340s^{-1}[/tex]
T = time period of a sound wave = ?
Now put all the given values in the above expression, we get the time period of the a sound wave.
[tex]T=\frac{1}{\nu}=\frac{1}{340s^{-1}}=2.94\times 10^{-3}s[/tex]
Therefore, the period of a sound wave is, [tex]2.4\times 10^{-3}s[/tex]
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