Answered

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What is the period of a sound wave having a
frequency of 340. hertz?
(1) 3.40 × 10^2 s (3) 9.73 × 10^−1 s
(2) 1.02 × 10^0 s (4) 2.94 × 10^−3 s


Sagot :

4)2.94 • 10^-3 s Period=(1/frequency) Period=(1/340Hz) Period=.0029411765 s

Answer : The correct option is, (4) [tex]2.4\times 10^{-3}s[/tex]

Solution :

The relation between the frequency and time period is that the frequency is inversely proportional to the time period.

It is written as,

[tex]\nu=\frac{1}{T}\\\\T=\frac{1}{\nu}[/tex]

where,

[tex]\nu[/tex] = frequency of the sound wave = 340 Hz = [tex]340s^{-1}[/tex]

T = time period of a sound wave = ?

Now put all the given values in the above expression, we get the time period of the a sound wave.

[tex]T=\frac{1}{\nu}=\frac{1}{340s^{-1}}=2.94\times 10^{-3}s[/tex]

Therefore, the period of a sound wave is, [tex]2.4\times 10^{-3}s[/tex]

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