Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
4)2.94 • 10^-3 s
Period=(1/frequency)
Period=(1/340Hz)
Period=.0029411765 s
Answer : The correct option is, (4) [tex]2.4\times 10^{-3}s[/tex]
Solution :
The relation between the frequency and time period is that the frequency is inversely proportional to the time period.
It is written as,
[tex]\nu=\frac{1}{T}\\\\T=\frac{1}{\nu}[/tex]
where,
[tex]\nu[/tex] = frequency of the sound wave = 340 Hz = [tex]340s^{-1}[/tex]
T = time period of a sound wave = ?
Now put all the given values in the above expression, we get the time period of the a sound wave.
[tex]T=\frac{1}{\nu}=\frac{1}{340s^{-1}}=2.94\times 10^{-3}s[/tex]
Therefore, the period of a sound wave is, [tex]2.4\times 10^{-3}s[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
