Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
pH = -log( [H3O+] )
so the pH is in powers of 10
1* 10^ 5 / 1*10^3 = 1* 10^2 = 100
so the answer is:
D. 100 times the original content
so the pH is in powers of 10
1* 10^ 5 / 1*10^3 = 1* 10^2 = 100
so the answer is:
D. 100 times the original content
Answer : The correct option is, (D) 100 times the original content.
Explanation :
As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3
As we know that,
[tex]pH=-\log [H_3O^+][/tex]
The hydronium ion concentration at pH = 5.
[tex]5=-\log [H_3O^+][/tex]
[tex][H_3O^+]=1\times 10^{-5}M[/tex] ..............(1)
The hydronium ion concentration at pH = 3.
[tex]3=-\log [H_3O^+][/tex]
[tex][H_3O^+]=1\times 10^{-3}M[/tex] ................(2)
By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.
[tex]\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}[/tex]
[tex]100\times [H_3O^+]_{original}=[H_3O^+]_{final}[/tex]
From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.
Hence, the correct option is, (D) 100 times the original content.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.