Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
17.6% oxygen
% mass = molar mass of part over molar mass of whole,
molar mass of oxygen is 16
molar mass of carbon is 12
molar mass of hydrogen is 1
so (16) / (16+12*6+3) = 16/91 = 17.58%
% mass = molar mass of part over molar mass of whole,
molar mass of oxygen is 16
molar mass of carbon is 12
molar mass of hydrogen is 1
so (16) / (16+12*6+3) = 16/91 = 17.58%
Answer : The percent by mass of oxygen in propanal is, 27.58 %
Solution : Given,
Molar mass of carbon = 12 g/mole
Molar mass of hydrogen = 1 g/mole
Molar mass of oxygen = 16 g/mole
First we have to calculate the molar mass of propanal, [tex]CH_3CH_2CHO[/tex]
Molar mass of propanal, [tex]CH_3CH_2CHO[/tex] = [tex]3(12)+6(1)+16=58g/mole[/tex]
Now we have to calculate the percent by mass of oxygen in propanal.
[tex]\text{Percent by mass of oxygen}=\frac{\text{Mass of oxygen}}{\text{Mass of propanal}}\times 100=\frac{16}{58}\times 100=27.58\%[/tex]
Therefore, the percent by mass of oxygen in propanal is, 27.58 %
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
