Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Find the vertex of the function f (x) = x^2+6x-2

Sagot :

f(x)=x^2+6x-2, vertex: (-3, -11)
First, put -(6)/2(1) or -b/2a.
You then get -3 as the X value of the vertex.
Next, insert -3 back into the equation to get the Y value of the vertex.
(-3)^2+6(-3)-2 = -11
You then have -11 as the Y value of the vertex.


Panoyin
X - Vertex
[tex]-\frac{6}{2(1)} = -\frac{6}{2} = -3[/tex]

Y - Vertex
[tex]f(x) = x^{2} + 6x - 2 \\f(-3) = (-3)^{2} + 6(-3) - 2 \\f(-3) = 9 - 18 - 2 \\f(-3) = -9 - 2 \\f(-3) = -11[/tex]

Vertex
(x, y) = (3, -11)
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.