Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Find the vertex of the function f (x) = x^2+6x-2

Sagot :

f(x)=x^2+6x-2, vertex: (-3, -11)
First, put -(6)/2(1) or -b/2a.
You then get -3 as the X value of the vertex.
Next, insert -3 back into the equation to get the Y value of the vertex.
(-3)^2+6(-3)-2 = -11
You then have -11 as the Y value of the vertex.


Panoyin
X - Vertex
[tex]-\frac{6}{2(1)} = -\frac{6}{2} = -3[/tex]

Y - Vertex
[tex]f(x) = x^{2} + 6x - 2 \\f(-3) = (-3)^{2} + 6(-3) - 2 \\f(-3) = 9 - 18 - 2 \\f(-3) = -9 - 2 \\f(-3) = -11[/tex]

Vertex
(x, y) = (3, -11)
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.