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Sagot :
I found (2).
Using [tex]E=m c^{2} =9.11* 10^{-31}* (3*10^{8} )^{2} =8.2* 10^{-14}J [/tex]
Using [tex]E=m c^{2} =9.11* 10^{-31}* (3*10^{8} )^{2} =8.2* 10^{-14}J [/tex]
Answer:
The correct answer is option 2,
The total energy released is [tex]8.20 * 10^{-14} J\\[/tex]
Explanation:
As per Einstein theory of relativity,
[tex]E = mc^2\\[/tex]
where
"E" is the energy produced by mass conversion
"m" is the mass converted
"c" speed of light
Substituting the given values in above equation we get -
[tex]E = (9.11 * 10^{-31}) Kg * ( 3 * 10^{8} \frac{m}{s} )^2\\= 8.20 * 10^{-14} J\\[/tex]
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