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Sagot :
Considering Conservation of Momentum, the momentum [tex]p=mv[/tex] before and after must remain the same:
so:
before: [tex]7.28*8.50-5.45*10.0=7.38 kg \frac{m}{s} [/tex]
so:
before: [tex]7.28*8.50-5.45*10.0=7.38 kg \frac{m}{s} [/tex]
The magnitude of the total momentum will be "7.38 kg.ms⁻¹".
Given:
Mass,
- [tex]m_1 = 7.28 \ kg[/tex]
- [tex]m_2 = 5.45 \ mg[/tex]
Speed,
- [tex]v_1 = 8.5 \ m/s[/tex]
- [tex]v_2 = 10 \ m/s[/tex]
By using the law of conservation of linear momentum, we get
→ [tex]P_{initial} = P_{final}[/tex]
or,
→ [tex]P_{final } = m_1\vec{v_{1i}}+m_2\vec{v_{2i}}[/tex]
By substituting the values, we get
[tex]|P_{final}|= 7.28\times 8.5-5.45\times 10[/tex]
[tex]=61.88-54.5[/tex]
[tex]= 7.38 \ kg.ms^{-1}[/tex]
Thus the above approach is correct.
Learn more about momentum here:
https://brainly.com/question/12091981
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