Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
5x = 6x² - 3
5x - 5x = 6x² - 5x - 3
0 = 6x² - 5x - 3
x = -(-5) ± √((-5)² - 4(6)(-3))
2(6)
x = 5 ± √(25 + 72)
12
x = 5 ± √(97)
12
x = 5 + √(97) U x = 5 - √(97)
12 12
[tex]the\ values\ of\ x\ is\ \frac{5 +/- \sqrt{97}}{12}.[/tex]
5x - 5x = 6x² - 5x - 3
0 = 6x² - 5x - 3
x = -(-5) ± √((-5)² - 4(6)(-3))
2(6)
x = 5 ± √(25 + 72)
12
x = 5 ± √(97)
12
x = 5 + √(97) U x = 5 - √(97)
12 12
[tex]the\ values\ of\ x\ is\ \frac{5 +/- \sqrt{97}}{12}.[/tex]
The value of x are; x = 5 + √(97)/12 and x = 5 - √(97)/12.
What is a quadratic equation?
A quadratic equation is the second-order degree algebraic expression in a variable.
The standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
Given;
5x = 6x² - 3
Subtract 5x on both sides
5x - 5x = 6x² - 5x - 3
0 = 6x² - 5x - 3
x = -(-5) ± √((-5)² - 4(6)(-3)) / 2(6)
x = 5 ± √(25 + 72)/ 12
x = 5 ± √(97)/ 12
The value of x are;
x = 5 + √(97)/12
x = 5 - √(97)/12
Learn more about quadratic equations;
brainly.com/question/13197897
#SPJ5
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
