Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Sagot :

Panoyin
       5x = 6x² - 3
5x - 5x = 6x² - 5x - 3
         0 = 6x² - 5x - 3
         x = -(-5) ± √((-5)² - 4(6)(-3))
                              2(6)
         x = 5 ± √(25 + 72)
                        12
         x = 5 ± √(97)
                   12
          x = 5 + √(97)    U    x = 5 - √(97)
                     12                          12
[tex]the\ values\ of\ x\ is\ \frac{5 +/- \sqrt{97}}{12}.[/tex]

The value of x are;  x = 5 + √(97)/12  and x = 5 - √(97)/12.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable.

The standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given;

 5x = 6x² - 3

Subtract 5x on both sides

5x - 5x = 6x² - 5x - 3

0 = 6x² - 5x - 3

       

x = -(-5) ± √((-5)² - 4(6)(-3)) / 2(6)

                           

x = 5 ± √(25 + 72)/ 12

x = 5 ± √(97)/ 12

               

The value of x are;

x = 5 + √(97)/12      

x = 5 - √(97)/12

                   

Learn more about quadratic equations;

brainly.com/question/13197897

#SPJ5

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.