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Sagot :
X - Intercept
x + 3y + 2z = 6
x + 3(0) + 2(0) = 6
x + 0 + 0 = 6
x + 0 = 6
- 0 - 0
x = 6
X - Intercept: (6, 0, 0)
Y - Intercept
x + 3y + 2z = 6
0 + 3y + 2(0) = 6
0 + 3y + 0 = 6
0 + 0 + 3y = 6
0 + 3y = 6
- 0 - 0
3y = 6
3 3
y = 2
Y - Intercept: (0, 2, 0)
Z - Intercept
x + 3y + 2z = 6
0 + 3(0) 2z = 6
0 + 0 + 2z = 6
0 + 2z = 6
- 0 - 0
2z = 6
2 2
z = 3
Z - Intercept: (0, 0, 3)
Volume of the X - Intercept, Y - Intercept, and Z - Intercept
V = ¹/₃(¹/₂lwh)
V = ¹/₃(¹/₂(6)(2)(3))
V = ¹/₃(¹/₂(12)(3))
V = ¹/₃(¹/₂(36))
V = ¹/₃(18)
V = 6 u³
x + 3y + 2z = 6
x + 3(0) + 2(0) = 6
x + 0 + 0 = 6
x + 0 = 6
- 0 - 0
x = 6
X - Intercept: (6, 0, 0)
Y - Intercept
x + 3y + 2z = 6
0 + 3y + 2(0) = 6
0 + 3y + 0 = 6
0 + 0 + 3y = 6
0 + 3y = 6
- 0 - 0
3y = 6
3 3
y = 2
Y - Intercept: (0, 2, 0)
Z - Intercept
x + 3y + 2z = 6
0 + 3(0) 2z = 6
0 + 0 + 2z = 6
0 + 2z = 6
- 0 - 0
2z = 6
2 2
z = 3
Z - Intercept: (0, 0, 3)
Volume of the X - Intercept, Y - Intercept, and Z - Intercept
V = ¹/₃(¹/₂lwh)
V = ¹/₃(¹/₂(6)(2)(3))
V = ¹/₃(¹/₂(12)(3))
V = ¹/₃(¹/₂(36))
V = ¹/₃(18)
V = 6 u³
Answer:
Volume of the pyramid = 6 cubic units
Step-by-step explanation:
The volume of a triangular pyramid is: V = (1/3)*A*H
where A is the area of the triangle base, and H is the height of the pyramid.
Taking the triangle formed in the x-y plane as the base, its area is computed as follows:
A = (1/2)*6*2 = 6 square units
where 6 and 2 are the measure of the two perpendicular sides of the triangle. This is taken from the x-intercept point (6, 0, 0) and y-intercept point (0, 2, 0).
The height of the pyramid is then the measure of the z-intercept point (0, 0, 3), that is, 3. Replacing in volume formula:
V = (1/3)*A*H
V = (1/3)*6*3
V = 6 cubic units
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