Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What is the change in temperature if 24g of water at 50°C absorbs 985 J of heat energy?



Sagot :

astonkute8
The formula is q=M*C*(Change in T)
q= 985 J
M= 24g
C= 4.186 j/gram (it's waters specific heat) 
Change in T= X (unknown) 

Once you solve for X, you should get 9.8, at least that's what I got. 
So the change in temperature is 9.8 C. 
sebassandin

Answer:

[tex]\Delta T=9.82^oC[/tex]

Explanation:

Hello,

In this case, we consider such heat absorption as an energy inlet, that is why the temperature of the water will raise as shown below as a positive result is obtained, considering water's heat capacity as 4.18 J/(g*°C):

[tex]Q=mCp\Delta T\\\Delta T=\frac{Q}{mCp}=\frac{985J}{24g*4.18\frac{J}{g^oC} }\\\\\Delta T=9.82^oC[/tex]

Best regards.

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.