Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A globe had a diameter of 17.8. It fits inside a cube-shaped box that has a side length of 17.8. What is the volume of the space inside the box that is not taken up by the globe?

Use 3.14 as pie. Round to the nearest hundredth


Sagot :

Answer:

Step-by-step explanation:

volume of box       -        volume of sphere    = unused space

L X W X H              -         4/3 pi r^3

17. 8 x 17.8 x 17.8   -   4/3 ( 3.14) ( 17.8/2)^3   = 2688.28 units^3

Answer:

Volume not taken up by the globe is 2688.28 units^3.

Step-by-step explanation:

To solve this problem, we require two formulas: the volume of a sphere and the volume of a cube. They are..

[tex]V_{c} = a^3 \\V_{s} = \frac{4}{3} \pi r^3[/tex]

Our given values are:

globe diameter of 17.8 units

cube side length of 17.8 units

To, get the volume of the sphere, we need the radius which can be obtained by dividing the diameter by 2.

17.8/2 = 8.9

radius of globe = 8.9 units

Now we can solve for the volumes of both objects.

[tex]V_{c} = a^3 \\V_{c} = 17.8^3 \\V_{c} = 5639.752 units^3[/tex]

[tex]V_{s} = \frac{4}{3} \pi (r^3)\\V_{s} = \frac{4}{3} \pi (8.9^3)\\V_{s} = \frac{4}{3} \pi (r^3) \\V_{s} = 2951.470213 units^3[/tex]

[tex]V_{nt} = 5639.752 - 2951.470213 \\V_{nt} = 2688.281787 \\[/tex]

Round to nearest hundredth.

V = 2688.28