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If ∆ = 6, which of the following is true? a) ∆ + 2 = 6 – 2 b) ∆ + 4 = 6 + 4 c) 10 − ∆= 10 − 4 d) ∆ + 3 = 3 + 3

Sagot :

reinhard10158

Step-by-step explanation:

just put 6 instead of every delta symbol and simply see, if both sides are equal or not.

a) 6 + 2 = 6 - 2 false (8 is not equal to 4)

b) 6 + 4 = 6 + 4 true (10 is equal to 10)

c) 10 - 6 = 10 - 4 false (4 is not equal to 6)

d) 6 + 3 = 3 + 3 false (9 is not equal to 6)

so, you see, if you just apply the rules consequently and consistently, you will get the right result. math is that way.

but if you let yourself get confused and you start guessing left and right, you will be wrong.

chibabykalu16

Answer:

∆ + 4 = 6 + 4

Step-by-step explanation:

Given:

  • ∆ = 6

To determine the truth value of the equations we can verify the options:

a) ∆ + 2 = 6 – 2

6 + 2 = 6 - 2

8 ≠ 4 (This option is false)

b) ∆ + 4 = 6 + 4

6 + 4 = 6 + 4

10 = 10 ( this option is true)

c) 10 − ∆= 10 − 4

10 - 6 = 10 - 4

4 ≠ 6 (This option is false)

d) ∆ + 3 = 3 + 3

6 + 3 = 3 + 3

9 ≠ 6 (This option is false)

Therefore, the only true value is:

[tex]\boxed{\boxed{\triangle + 4 = 6 + 4}}[/tex]

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