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I’m stuck

Find l.
l
15 in.
l = √ [?] in
12 in.
Enter


Im Stuck Find Ll15 Inl In12 InEnter class=

Sagot :

Answer:

l = [tex]\sqrt{261}[/tex] in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

• c² = a² + b² ( c is the hypotenuse and a, b the legs )

Note the diameter = 12 in, then radius = 12 ÷ 2 = 6 in

let a = radius = 6 , b = height = 15 and c = l , then

l² = 6² + 15² = 36 + 225 = 261 ( take square root of both sides )

[tex]\sqrt{l^2}[/tex] = [tex]\sqrt{261}[/tex]

l = [tex]\sqrt{261}[/tex] in