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law of cosines. pls help me

Law Of Cosines Pls Help Me class=

Sagot :

Answer:

X = 52.4°

Step-by-step explanation:

[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \: CosA[/tex]

In the diagram, X = A, therefore;

[tex]CosA \: = \frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} [/tex]

[tex]Cos \: X \: = \frac{ {{5}^{2} + {10}^{2} - {8}^{2} } }{2 \times 5 \times 10} [/tex]

[tex] = \frac{100 + 25 - 64}{100} [/tex]

[tex] = \frac{61}{100} = 0.61

X = arc cos (0.61)

X = 52. 4105°

X = 52.4°