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If 3 1/6 + x = 19/ 42, find the value of x.

Sagot :

Answer: Answer below

1. Make improper fractions:

[tex]\frac{3 * 6 + 1}{6} + x = \frac{19}{42} =
\\ \\ \\
\frac{19}{6} + x = \frac{19}{42} =
\\ \\ \\
x = \frac{19}{42} - \frac{19 * 7}{6 * 7} =
\\ \\ \\
x = \frac{19}{42} - \frac{133}{42} =
\\ \\ \\
x = \frac{-114 : 2}{42 : 2} = -\frac{57 : 3}{21 : 3} = -\frac{19}{7} = -2\frac{5}{7}[/tex]

So this is the answer. Hope this helps!
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